Base | Representation |
---|---|
bin | 10111101100110000010111… |
… | …11011101000011011010101 |
3 | 20211112011210012001101211011 |
4 | 23312120023323220123111 |
5 | 23312324200314214000 |
6 | 302501241552212221 |
7 | 13656131354300242 |
oct | 1366301373503325 |
9 | 224464705041734 |
10 | 52115333351125 |
11 | 15672a9703a690 |
12 | 5a1837383a071 |
13 | 23105bb3b9cc5 |
14 | cc25777145c9 |
15 | 60598d0872ba |
hex | 2f660bee86d5 |
52115333351125 has 16 divisors (see below), whose sum is σ = 70952657480640. Its totient is φ = 37902060618000.
The previous prime is 52115333351113. The next prime is 52115333351143.
52115333351125 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 52115333351125 - 25 = 52115333351093 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18951028935 + ... + 18951031684.
It is an arithmetic number, because the mean of its divisors is an integer number (4434541092540).
Almost surely, 252115333351125 is an apocalyptic number.
52115333351125 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52115333351125 is a deficient number, since it is larger than the sum of its proper divisors (18837324129515).
52115333351125 is a wasteful number, since it uses less digits than its factorization.
52115333351125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37902060645 (or 37902060635 counting only the distinct ones).
The product of its digits is 202500, while the sum is 40.
It can be divided in two parts, 5211533 and 3351125, that added together give a palindrome (8562658).
The spelling of 52115333351125 in words is "fifty-two trillion, one hundred fifteen billion, three hundred thirty-three million, three hundred fifty-one thousand, one hundred twenty-five".
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