Base | Representation |
---|---|
bin | 10111101100111001010101… |
… | …01011000011010001000001 |
3 | 20211112122012110021000110101 |
4 | 23312130222223003101001 |
5 | 23312414023340044401 |
6 | 302503355202402401 |
7 | 13656361520554003 |
oct | 1366345253032101 |
9 | 224478173230411 |
10 | 52120144065601 |
11 | 15675035612677 |
12 | 5a19296960401 |
13 | 2310ba6c73411 |
14 | cc28b25c2373 |
15 | 605b7059e101 |
hex | 2f672aac3441 |
52120144065601 has 2 divisors, whose sum is σ = 52120144065602. Its totient is φ = 52120144065600.
The previous prime is 52120144065569. The next prime is 52120144065673. The reversal of 52120144065601 is 10656044102125.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35235811072576 + 16884332993025 = 5935976^2 + 4109055^2 .
It is a cyclic number.
It is not a de Polignac number, because 52120144065601 - 25 = 52120144065569 is a prime.
It is not a weakly prime, because it can be changed into another prime (52120144065901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26060072032800 + 26060072032801.
It is an arithmetic number, because the mean of its divisors is an integer number (26060072032801).
Almost surely, 252120144065601 is an apocalyptic number.
It is an amenable number.
52120144065601 is a deficient number, since it is larger than the sum of its proper divisors (1).
52120144065601 is an equidigital number, since it uses as much as digits as its factorization.
52120144065601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 52120144065601 its reverse (10656044102125), we get a palindrome (62776188167726).
The spelling of 52120144065601 in words is "fifty-two trillion, one hundred twenty billion, one hundred forty-four million, sixty-five thousand, six hundred one".
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