Base | Representation |
---|---|
bin | 1001101101011000… |
… | …10000110011110011 |
3 | 111110021022110211111 |
4 | 10312230100303303 |
5 | 41133402241042 |
6 | 2221122454151 |
7 | 243112601023 |
oct | 46654206363 |
9 | 14407273744 |
10 | 5212540147 |
11 | 2235385621 |
12 | 1015804357 |
13 | 650bb69a9 |
14 | 3763c9a83 |
15 | 20793b517 |
hex | 136b10cf3 |
5212540147 has 2 divisors, whose sum is σ = 5212540148. Its totient is φ = 5212540146.
The previous prime is 5212540141. The next prime is 5212540181. The reversal of 5212540147 is 7410452125.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5212540147 - 23 = 5212540139 is a prime.
It is not a weakly prime, because it can be changed into another prime (5212540141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2606270073 + 2606270074.
It is an arithmetic number, because the mean of its divisors is an integer number (2606270074).
Almost surely, 25212540147 is an apocalyptic number.
5212540147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5212540147 is an equidigital number, since it uses as much as digits as its factorization.
5212540147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11200, while the sum is 31.
The square root of 5212540147 is about 72197.9234258161. The cubic root of 5212540147 is about 1733.8697549515.
The spelling of 5212540147 in words is "five billion, two hundred twelve million, five hundred forty thousand, one hundred forty-seven".
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