Base | Representation |
---|---|
bin | 10111101101001111011010… |
… | …10111000101001101000011 |
3 | 20211120202210201220021011111 |
4 | 23312213231113011031003 |
5 | 23313112314040303441 |
6 | 302513035455224151 |
7 | 13660261365230164 |
oct | 1366475527051503 |
9 | 224522721807144 |
10 | 52132000322371 |
11 | 1567a06a115892 |
12 | 5a1b645518057 |
13 | 23120463b9b78 |
14 | cc32b90a376b |
15 | 6061163c9081 |
hex | 2f69ed5c5343 |
52132000322371 has 2 divisors, whose sum is σ = 52132000322372. Its totient is φ = 52132000322370.
The previous prime is 52132000322321. The next prime is 52132000322393. The reversal of 52132000322371 is 17322300023125.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52132000322371 - 245 = 16947628233539 is a prime.
It is a super-2 number, since 2×521320003223712 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52132000322321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26066000161185 + 26066000161186.
It is an arithmetic number, because the mean of its divisors is an integer number (26066000161186).
Almost surely, 252132000322371 is an apocalyptic number.
52132000322371 is a deficient number, since it is larger than the sum of its proper divisors (1).
52132000322371 is an equidigital number, since it uses as much as digits as its factorization.
52132000322371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 52132000322371 its reverse (17322300023125), we get a palindrome (69454300345496).
The spelling of 52132000322371 in words is "fifty-two trillion, one hundred thirty-two billion, three hundred twenty-two thousand, three hundred seventy-one".
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