Base | Representation |
---|---|
bin | 10111101101010001010110… |
… | …11010011110110101000011 |
3 | 20211120212111021212112202222 |
4 | 23312220223122132311003 |
5 | 23313121432044314110 |
6 | 302513331045201255 |
7 | 13660326236241251 |
oct | 1366505332366503 |
9 | 224525437775688 |
10 | 52133041401155 |
11 | 1567a553846780 |
12 | 5a1b89610022b |
13 | 2312180caa910 |
14 | cc33774655d1 |
15 | 6061779c1c55 |
hex | 2f6a2b69ed43 |
52133041401155 has 32 divisors (see below), whose sum is σ = 73504827648000. Its totient is φ = 34994511953280.
The previous prime is 52133041401137. The next prime is 52133041401157. The reversal of 52133041401155 is 55110414033125.
It is a happy number.
It is a de Polignac number, because none of the positive numbers 2k-52133041401155 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52133041401157) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2383094 + ... + 10485476.
It is an arithmetic number, because the mean of its divisors is an integer number (2297025864000).
Almost surely, 252133041401155 is an apocalyptic number.
52133041401155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
52133041401155 is a deficient number, since it is larger than the sum of its proper divisors (21371786246845).
52133041401155 is a wasteful number, since it uses less digits than its factorization.
52133041401155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8111411.
The product of its (nonzero) digits is 36000, while the sum is 35.
The spelling of 52133041401155 in words is "fifty-two trillion, one hundred thirty-three billion, forty-one million, four hundred one thousand, one hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •