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52137955437 = 317379318479
BaseRepresentation
bin110000100011101010…
…100001000001101101
311222120120202120010120
4300203222201001231
51323234304033222
635541333155153
73524012210661
oct604352410155
9158516676116
1052137955437
1120125575677
12a130a8bab9
134bbb989909
14274865a8a1
15155240815c
hexc23aa106d

52137955437 has 4 divisors (see below), whose sum is σ = 69517273920. Its totient is φ = 34758636956.

The previous prime is 52137955433. The next prime is 52137955459. The reversal of 52137955437 is 73455973125.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52137955437 - 22 = 52137955433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52137955437.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52137955433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8689659237 + ... + 8689659242.

It is an arithmetic number, because the mean of its divisors is an integer number (17379318480).

Almost surely, 252137955437 is an apocalyptic number.

It is an amenable number.

52137955437 is a deficient number, since it is larger than the sum of its proper divisors (17379318483).

52137955437 is a wasteful number, since it uses less digits than its factorization.

52137955437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17379318482.

The product of its digits is 3969000, while the sum is 51.

The spelling of 52137955437 in words is "fifty-two billion, one hundred thirty-seven million, nine hundred fifty-five thousand, four hundred thirty-seven".

Divisors: 1 3 17379318479 52137955437