Base | Representation |
---|---|
bin | 1111001011001011110… |
… | …00100111101111011001 |
3 | 1211211211021210212211212 |
4 | 13211211320213233121 |
5 | 32020311444300343 |
6 | 1035310015432505 |
7 | 52445534066663 |
oct | 7454570475731 |
9 | 1754737725755 |
10 | 521400384473 |
11 | 191140a19061 |
12 | 85073b25735 |
13 | 3a2249aa177 |
14 | 1b3434bb533 |
15 | d8697bcc18 |
hex | 7965e27bd9 |
521400384473 has 2 divisors, whose sum is σ = 521400384474. Its totient is φ = 521400384472.
The previous prime is 521400384451. The next prime is 521400384503. The reversal of 521400384473 is 374483004125.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 463669750489 + 57730633984 = 680933^2 + 240272^2 .
It is a cyclic number.
It is not a de Polignac number, because 521400384473 - 228 = 521131949017 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 521400384473.
It is not a weakly prime, because it can be changed into another prime (521400384403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260700192236 + 260700192237.
It is an arithmetic number, because the mean of its divisors is an integer number (260700192237).
Almost surely, 2521400384473 is an apocalyptic number.
It is an amenable number.
521400384473 is a deficient number, since it is larger than the sum of its proper divisors (1).
521400384473 is an equidigital number, since it uses as much as digits as its factorization.
521400384473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 322560, while the sum is 41.
Adding to 521400384473 its reverse (374483004125), we get a palindrome (895883388598).
The spelling of 521400384473 in words is "five hundred twenty-one billion, four hundred million, three hundred eighty-four thousand, four hundred seventy-three".
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