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52143800256847 = 139294317612011
BaseRepresentation
bin10111101101100101011001…
…01100010000100101001111
320211121220021002120001012201
423312302230230100211033
523313311000331204342
6302522310420542331
713661156660064415
oct1366625454204517
9224556232501181
1052143800256847
111568407494a252
125a219992519a7
1323131a6c73610
14cc3ab82c32b5
156065a72cadb7
hex2f6cacb1094f

52143800256847 has 8 divisors (see below), whose sum is σ = 56215308396240. Its totient is φ = 48080927343360.

The previous prime is 52143800256839. The next prime is 52143800256851. The reversal of 52143800256847 is 74865200834125.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 52143800256847 - 23 = 52143800256839 is a prime.

It is a super-3 number, since 3×521438002568473 (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52143800256857) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2158793929 + ... + 2158818082.

It is an arithmetic number, because the mean of its divisors is an integer number (7026913549530).

Almost surely, 252143800256847 is an apocalyptic number.

52143800256847 is a deficient number, since it is larger than the sum of its proper divisors (4071508139393).

52143800256847 is a wasteful number, since it uses less digits than its factorization.

52143800256847 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4317612953.

The product of its (nonzero) digits is 12902400, while the sum is 55.

The spelling of 52143800256847 in words is "fifty-two trillion, one hundred forty-three billion, eight hundred million, two hundred fifty-six thousand, eight hundred forty-seven".

Divisors: 1 13 929 12077 4317612011 56128956143 4011061558219 52143800256847