Base | Representation |
---|---|
bin | 10111101101100101011001… |
… | …01100011110010010111011 |
3 | 20211121220021002122220021011 |
4 | 23312302230230132102323 |
5 | 23313311000340004034 |
6 | 302522310422054351 |
7 | 13661156660420242 |
oct | 1366625454362273 |
9 | 224556232586234 |
10 | 52143800313019 |
11 | 15684074988478 |
12 | 5a2199927a3b7 |
13 | 23131a6c9305c |
14 | cc3ab82d9959 |
15 | 6065a72dc864 |
hex | 2f6cacb1e4bb |
52143800313019 has 2 divisors, whose sum is σ = 52143800313020. Its totient is φ = 52143800313018.
The previous prime is 52143800312927. The next prime is 52143800313107. The reversal of 52143800313019 is 91031300834125.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52143800313019 - 245 = 16959428224187 is a prime.
It is a super-3 number, since 3×521438003130193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (52143800383019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26071900156509 + 26071900156510.
It is an arithmetic number, because the mean of its divisors is an integer number (26071900156510).
Almost surely, 252143800313019 is an apocalyptic number.
52143800313019 is a deficient number, since it is larger than the sum of its proper divisors (1).
52143800313019 is an equidigital number, since it uses as much as digits as its factorization.
52143800313019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 52143800313019 in words is "fifty-two trillion, one hundred forty-three billion, eight hundred million, three hundred thirteen thousand, nineteen".
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