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52242547073 is a prime number
BaseRepresentation
bin110000101001111001…
…100000000110000001
311222211212120100212212
4300221321200012001
51323443043001243
635555551031505
73526422215603
oct605171400601
9158755510785
1052242547073
1120179612942
12a15bb0b595
134c0754a362
1427584c5173
15155b6b8318
hexc29e60181

52242547073 has 2 divisors, whose sum is σ = 52242547074. Its totient is φ = 52242547072.

The previous prime is 52242547037. The next prime is 52242547087. The reversal of 52242547073 is 37074524225.

Together with previous prime (52242547037) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48003495409 + 4239051664 = 219097^2 + 65108^2 .

It is a cyclic number.

It is not a de Polignac number, because 52242547073 - 220 = 52241498497 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 52242547073.

It is not a weakly prime, because it can be changed into another prime (52242547013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26121273536 + 26121273537.

It is an arithmetic number, because the mean of its divisors is an integer number (26121273537).

Almost surely, 252242547073 is an apocalyptic number.

It is an amenable number.

52242547073 is a deficient number, since it is larger than the sum of its proper divisors (1).

52242547073 is an equidigital number, since it uses as much as digits as its factorization.

52242547073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 470400, while the sum is 41.

The spelling of 52242547073 in words is "fifty-two billion, two hundred forty-two million, five hundred forty-seven thousand, seventy-three".