Base | Representation |
---|---|
bin | 10111110001000000010001… |
… | …00010000111000110101111 |
3 | 20212001010120012212112002210 |
4 | 23320200020202013012233 |
5 | 23322222123113424310 |
6 | 303052302344021503 |
7 | 14002516601551455 |
oct | 1370401042070657 |
9 | 225033505775083 |
10 | 52261305217455 |
11 | 15719993389344 |
12 | 5a40711461893 |
13 | 23212b22773c9 |
14 | cc966410a9d5 |
15 | 6096831d5820 |
hex | 2f88088871af |
52261305217455 has 32 divisors (see below), whose sum is σ = 88022163398400. Its totient is φ = 26404775200512.
The previous prime is 52261305217427. The next prime is 52261305217519. The reversal of 52261305217455 is 55471250316225.
It is not a de Polignac number, because 52261305217455 - 27 = 52261305217327 is a prime.
It is a super-3 number, since 3×522613052174553 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4828491 + ... + 11306499.
It is an arithmetic number, because the mean of its divisors is an integer number (2750692606200).
Almost surely, 252261305217455 is an apocalyptic number.
52261305217455 is a deficient number, since it is larger than the sum of its proper divisors (35760858180945).
52261305217455 is a wasteful number, since it uses less digits than its factorization.
52261305217455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6506343.
The product of its (nonzero) digits is 2520000, while the sum is 48.
The spelling of 52261305217455 in words is "fifty-two trillion, two hundred sixty-one billion, three hundred five million, two hundred seventeen thousand, four hundred fifty-five".
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