Base | Representation |
---|---|
bin | 111011011111100010011101… |
… | …1101111001010100010111001 |
3 | 2112121212101101100200201010012 |
4 | 1312333010323233022202321 |
5 | 1022042303310302003031 |
6 | 5052550331314231305 |
7 | 215140321513220360 |
oct | 16677047357124271 |
9 | 2477771340621105 |
10 | 523304112531641 |
11 | 141817034017761 |
12 | 4a837a14585535 |
13 | 195cc49b33839c |
14 | 93320a899a7d7 |
15 | 407751a739b2b |
hex | 1dbf13bbca8b9 |
523304112531641 has 32 divisors (see below), whose sum is σ = 635844488578560. Its totient is φ = 420945776469504.
The previous prime is 523304112531581. The next prime is 523304112531643. The reversal of 523304112531641 is 146135211403325.
It is a cyclic number.
It is not a de Polignac number, because 523304112531641 - 222 = 523304108337337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (523304112531643) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1937820215 + ... + 1938090243.
It is an arithmetic number, because the mean of its divisors is an integer number (19870140268080).
Almost surely, 2523304112531641 is an apocalyptic number.
It is an amenable number.
523304112531641 is a deficient number, since it is larger than the sum of its proper divisors (112540376046919).
523304112531641 is a wasteful number, since it uses less digits than its factorization.
523304112531641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 497225.
The product of its (nonzero) digits is 259200, while the sum is 41.
Adding to 523304112531641 its reverse (146135211403325), we get a palindrome (669439323934966).
The spelling of 523304112531641 in words is "five hundred twenty-three trillion, three hundred four billion, one hundred twelve million, five hundred thirty-one thousand, six hundred forty-one".
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