Base | Representation |
---|---|
bin | 10111110011000100110000… |
… | …11111111110000110000111 |
3 | 20212021221011201121112110021 |
4 | 23321202120133332012013 |
5 | 23324403314123131403 |
6 | 303145105134240011 |
7 | 14010615435640111 |
oct | 1371423037760607 |
9 | 225257151545407 |
10 | 52332440052103 |
11 | 15747077118492 |
12 | 5a52464356007 |
13 | 2327c0a84b143 |
14 | cccc9172c3b1 |
15 | 60b44825d8bd |
hex | 2f98987fe187 |
52332440052103 has 4 divisors (see below), whose sum is σ = 52714428665760. Its totient is φ = 51950451438448.
The previous prime is 52332440052073. The next prime is 52332440052127. The reversal of 52332440052103 is 30125004423325.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52332440052103 - 213 = 52332440043911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52332440352103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190994306623 + ... + 190994306896.
It is an arithmetic number, because the mean of its divisors is an integer number (13178607166440).
Almost surely, 252332440052103 is an apocalyptic number.
52332440052103 is a deficient number, since it is larger than the sum of its proper divisors (381988613657).
52332440052103 is a wasteful number, since it uses less digits than its factorization.
52332440052103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 381988613656.
The product of its (nonzero) digits is 86400, while the sum is 34.
Adding to 52332440052103 its reverse (30125004423325), we get a palindrome (82457444475428).
The spelling of 52332440052103 in words is "fifty-two trillion, three hundred thirty-two billion, four hundred forty million, fifty-two thousand, one hundred three".
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