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52339146780001 is a prime number
BaseRepresentation
bin10111110011010001010000…
…10000000110110101100001
320212022120111010111121112211
423321220220100012311201
523330011033033430001
6303152134434522121
714011243564120504
oct1371505020066541
9225276433447484
1052339146780001
11157499a8973414
125a53816436341
1323287391706a3
14ccd32a34713b
1560b6dbe47351
hex2f9a28406d61

52339146780001 has 2 divisors, whose sum is σ = 52339146780002. Its totient is φ = 52339146780000.

The previous prime is 52339146779987. The next prime is 52339146780023. The reversal of 52339146780001 is 10008764193325.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 46720710915025 + 5618435864976 = 6835255^2 + 2370324^2 .

It is a cyclic number.

It is not a de Polignac number, because 52339146780001 - 219 = 52339146255713 is a prime.

It is not a weakly prime, because it can be changed into another prime (52339146780601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26169573390000 + 26169573390001.

It is an arithmetic number, because the mean of its divisors is an integer number (26169573390001).

It is a 2-persistent number, because it is pandigital, and so is 2⋅52339146780001 = 104678293560002, but 3⋅52339146780001 = 157017440340003 is not.

Almost surely, 252339146780001 is an apocalyptic number.

It is an amenable number.

52339146780001 is a deficient number, since it is larger than the sum of its proper divisors (1).

52339146780001 is an equidigital number, since it uses as much as digits as its factorization.

52339146780001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 52339146780001 in words is "fifty-two trillion, three hundred thirty-nine billion, one hundred forty-six million, seven hundred eighty thousand, one".