Base | Representation |
---|---|
bin | 100110000101011010111… |
… | …0100001101101101001011 |
3 | 200112101200210112101120122 |
4 | 1030022311310031231023 |
5 | 1141224342023432001 |
6 | 15044340314413455 |
7 | 1050111225256121 |
oct | 114126564155513 |
9 | 20471623471518 |
10 | 5234320530251 |
11 | 173895453204a |
12 | 70654343128b |
13 | 2bc7959055b7 |
14 | 1414b1a21911 |
15 | 91253c5bb1b |
hex | 4c2b5d0db4b |
5234320530251 has 2 divisors, whose sum is σ = 5234320530252. Its totient is φ = 5234320530250.
The previous prime is 5234320530097. The next prime is 5234320530311. The reversal of 5234320530251 is 1520350234325.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5234320530251 is a prime.
It is a super-2 number, since 2×52343205302512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5234320560251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2617160265125 + 2617160265126.
It is an arithmetic number, because the mean of its divisors is an integer number (2617160265126).
Almost surely, 25234320530251 is an apocalyptic number.
5234320530251 is a deficient number, since it is larger than the sum of its proper divisors (1).
5234320530251 is an equidigital number, since it uses as much as digits as its factorization.
5234320530251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 5234320530251 its reverse (1520350234325), we get a palindrome (6754670764576).
The spelling of 5234320530251 in words is "five trillion, two hundred thirty-four billion, three hundred twenty million, five hundred thirty thousand, two hundred fifty-one".
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