Base | Representation |
---|---|
bin | 110000110001000010… |
… | …110111001011011001 |
3 | 12000011020011122000201 |
4 | 300301002313023121 |
5 | 1324214241111213 |
6 | 40015512502201 |
7 | 3532406260051 |
oct | 606102671331 |
9 | 160136148021 |
10 | 52362441433 |
11 | 20230262295 |
12 | a1940aa961 |
13 | 4c26338173 |
14 | 276a3b4561 |
15 | 1566e9c6dd |
hex | c310b72d9 |
52362441433 has 2 divisors, whose sum is σ = 52362441434. Its totient is φ = 52362441432.
The previous prime is 52362441427. The next prime is 52362441437. The reversal of 52362441433 is 33414426325.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30909859344 + 21452582089 = 175812^2 + 146467^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52362441433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52362441392 and 52362441401.
It is not a weakly prime, because it can be changed into another prime (52362441437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26181220716 + 26181220717.
It is an arithmetic number, because the mean of its divisors is an integer number (26181220717).
Almost surely, 252362441433 is an apocalyptic number.
It is an amenable number.
52362441433 is a deficient number, since it is larger than the sum of its proper divisors (1).
52362441433 is an equidigital number, since it uses as much as digits as its factorization.
52362441433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 207360, while the sum is 37.
Adding to 52362441433 its reverse (33414426325), we get a palindrome (85776867758).
The spelling of 52362441433 in words is "fifty-two billion, three hundred sixty-two million, four hundred forty-one thousand, four hundred thirty-three".
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