Base | Representation |
---|---|
bin | 110000110011001111… |
… | …111011000001001111 |
3 | 12000020210202022100200 |
4 | 300303033323001033 |
5 | 1324303222410341 |
6 | 40023313224543 |
7 | 3533335500540 |
oct | 606317730117 |
9 | 160223668320 |
10 | 52399419471 |
11 | 2024a119453 |
12 | a1a4562153 |
13 | 4c30bb4369 |
14 | 277127c4c7 |
15 | 156a353db6 |
hex | c333fb04f |
52399419471 has 24 divisors (see below), whose sum is σ = 87294224160. Its totient is φ = 29667819456.
The previous prime is 52399419463. The next prime is 52399419511. The reversal of 52399419471 is 17491499325.
52399419471 is a `hidden beast` number, since 52 + 39 + 94 + 1 + 9 + 471 = 666.
It is not a de Polignac number, because 52399419471 - 23 = 52399419463 is a prime.
It is a super-3 number, since 3×523994194713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52399419431) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3808440 + ... + 3822173.
It is an arithmetic number, because the mean of its divisors is an integer number (3637259340).
Almost surely, 252399419471 is an apocalyptic number.
52399419471 is a deficient number, since it is larger than the sum of its proper divisors (34894804689).
52399419471 is a wasteful number, since it uses less digits than its factorization.
52399419471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7630735 (or 7630732 counting only the distinct ones).
The product of its digits is 2449440, while the sum is 54.
The spelling of 52399419471 in words is "fifty-two billion, three hundred ninety-nine million, four hundred nineteen thousand, four hundred seventy-one".
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