Base | Representation |
---|---|
bin | 100110001000100110001… |
… | …1000001100010010011001 |
3 | 200120001022011102010120011 |
4 | 1030101030120030102121 |
5 | 1141332324211330241 |
6 | 15051425220001521 |
7 | 1050442241534242 |
oct | 114211430142231 |
9 | 20501264363504 |
10 | 5241141511321 |
11 | 1740834824091 |
12 | 7079278302a1 |
13 | 2c0311abc081 |
14 | 14195b89bcc9 |
15 | 915029b3281 |
hex | 4c44c60c499 |
5241141511321 has 2 divisors, whose sum is σ = 5241141511322. Its totient is φ = 5241141511320.
The previous prime is 5241141511301. The next prime is 5241141511381. The reversal of 5241141511321 is 1231151411425.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4388769413721 + 852372097600 = 2094939^2 + 923240^2 .
It is a cyclic number.
It is not a de Polignac number, because 5241141511321 - 227 = 5241007293593 is a prime.
It is not a weakly prime, because it can be changed into another prime (5241141511301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2620570755660 + 2620570755661.
It is an arithmetic number, because the mean of its divisors is an integer number (2620570755661).
Almost surely, 25241141511321 is an apocalyptic number.
It is an amenable number.
5241141511321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5241141511321 is an equidigital number, since it uses as much as digits as its factorization.
5241141511321 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4800, while the sum is 31.
Adding to 5241141511321 its reverse (1231151411425), we get a palindrome (6472292922746).
The spelling of 5241141511321 in words is "five trillion, two hundred forty-one billion, one hundred forty-one million, five hundred eleven thousand, three hundred twenty-one".
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