Base | Representation |
---|---|
bin | 1111010000001111111… |
… | …11001101100111000001 |
3 | 1212002211211021202101222 |
4 | 13220013333031213001 |
5 | 32041344211141231 |
6 | 1040435531004425 |
7 | 52603116450512 |
oct | 7500777154701 |
9 | 1762754252358 |
10 | 524120021441 |
11 | 1923070a7615 |
12 | 856b2899715 |
13 | 3a56927aa03 |
14 | 1b520782a09 |
15 | d97843127b |
hex | 7a07fcd9c1 |
524120021441 has 2 divisors, whose sum is σ = 524120021442. Its totient is φ = 524120021440.
The previous prime is 524120021389. The next prime is 524120021521. The reversal of 524120021441 is 144120021425.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 458706843841 + 65413177600 = 677279^2 + 255760^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-524120021441 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 524120021441.
It is not a weakly prime, because it can be changed into another prime (524120021941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262060010720 + 262060010721.
It is an arithmetic number, because the mean of its divisors is an integer number (262060010721).
Almost surely, 2524120021441 is an apocalyptic number.
It is an amenable number.
524120021441 is a deficient number, since it is larger than the sum of its proper divisors (1).
524120021441 is an equidigital number, since it uses as much as digits as its factorization.
524120021441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 524120021441 its reverse (144120021425), we get a palindrome (668240042866).
The spelling of 524120021441 in words is "five hundred twenty-four billion, one hundred twenty million, twenty-one thousand, four hundred forty-one".
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