Base | Representation |
---|---|
bin | 1111010000011001111… |
… | …00101010111010101011 |
3 | 1212010001121212202100201 |
4 | 13220030330222322223 |
5 | 32042032012204011 |
6 | 1040452102413031 |
7 | 52605150013513 |
oct | 7501474527253 |
9 | 1763047782321 |
10 | 524203241131 |
11 | 19234a077819 |
12 | 85716731177 |
13 | 3a58059772b |
14 | 1b52b846843 |
15 | d9808bdcc1 |
hex | 7a0cf2aeab |
524203241131 has 2 divisors, whose sum is σ = 524203241132. Its totient is φ = 524203241130.
The previous prime is 524203241083. The next prime is 524203241147. The reversal of 524203241131 is 131142302425.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 524203241131 - 29 = 524203240619 is a prime.
It is a super-2 number, since 2×5242032411312 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 524203241131.
It is not a weakly prime, because it can be changed into another prime (524203241531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262101620565 + 262101620566.
It is an arithmetic number, because the mean of its divisors is an integer number (262101620566).
Almost surely, 2524203241131 is an apocalyptic number.
524203241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
524203241131 is an equidigital number, since it uses as much as digits as its factorization.
524203241131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 524203241131 its reverse (131142302425), we get a palindrome (655345543556).
The spelling of 524203241131 in words is "five hundred twenty-four billion, two hundred three million, two hundred forty-one thousand, one hundred thirty-one".
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