Base | Representation |
---|---|
bin | 10111110110000000100010… |
… | …00101111111110101111001 |
3 | 20212122120101011200020020211 |
4 | 23323000101011333311321 |
5 | 23333031242332100312 |
6 | 303303300144351121 |
7 | 14021114516254426 |
oct | 1373002105776571 |
9 | 225576334606224 |
10 | 52433247534457 |
11 | 157858a7334a79 |
12 | 5a69ab86154a1 |
13 | 233458473039a |
14 | cd3ad5b04d4d |
15 | 60dd982ec3a7 |
hex | 2fb01117fd79 |
52433247534457 has 2 divisors, whose sum is σ = 52433247534458. Its totient is φ = 52433247534456.
The previous prime is 52433247534307. The next prime is 52433247534461. The reversal of 52433247534457 is 75443574233425.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30284373759376 + 22148873775081 = 5503124^2 + 4706259^2 .
It is a cyclic number.
It is not a de Polignac number, because 52433247534457 - 215 = 52433247501689 is a prime.
It is not a weakly prime, because it can be changed into another prime (52433247534497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26216623767228 + 26216623767229.
It is an arithmetic number, because the mean of its divisors is an integer number (26216623767229).
Almost surely, 252433247534457 is an apocalyptic number.
It is an amenable number.
52433247534457 is a deficient number, since it is larger than the sum of its proper divisors (1).
52433247534457 is an equidigital number, since it uses as much as digits as its factorization.
52433247534457 is an evil number, because the sum of its binary digits is even.
The product of its digits is 169344000, while the sum is 58.
The spelling of 52433247534457 in words is "fifty-two trillion, four hundred thirty-three billion, two hundred forty-seven million, five hundred thirty-four thousand, four hundred fifty-seven".
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