Base | Representation |
---|---|
bin | 10111110110000001100000… |
… | …11110110010011111100011 |
3 | 20212122121201212112220112010 |
4 | 23323000300132302133203 |
5 | 23333033332134031300 |
6 | 303303424315204003 |
7 | 14021133542236035 |
oct | 1373006036623743 |
9 | 225577655486463 |
10 | 52433774127075 |
11 | 15786047604890 |
12 | 5a6a024a46603 |
13 | 2334639866553 |
14 | cd3b45a1dc55 |
15 | 60ddc9669a50 |
hex | 2fb0307b27e3 |
52433774127075 has 24 divisors (see below), whose sum is σ = 94571461699776. Its totient is φ = 25422435940000.
The previous prime is 52433774127073. The next prime is 52433774127121. The reversal of 52433774127075 is 57072147733425.
It is not a de Polignac number, because 52433774127075 - 21 = 52433774127073 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52433774127073) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31778044101 + ... + 31778045750.
It is an arithmetic number, because the mean of its divisors is an integer number (3940477570824).
Almost surely, 252433774127075 is an apocalyptic number.
52433774127075 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
52433774127075 is a deficient number, since it is larger than the sum of its proper divisors (42137687572701).
52433774127075 is a wasteful number, since it uses less digits than its factorization.
52433774127075 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63556089875 (or 63556089870 counting only the distinct ones).
The product of its (nonzero) digits is 34574400, while the sum is 57.
The spelling of 52433774127075 in words is "fifty-two trillion, four hundred thirty-three billion, seven hundred seventy-four million, one hundred twenty-seven thousand, seventy-five".
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