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5245500233 is a prime number
BaseRepresentation
bin1001110001010011…
…11111101101001001
3111112120100000120102
410320221333231021
541220322001413
62224301135145
7243663005411
oct47051775511
914476300512
105245500233
112251a47a66
12102485a4b5
136579870bc
1437a929641
1520a79c458
hex138a7fb49

5245500233 has 2 divisors, whose sum is σ = 5245500234. Its totient is φ = 5245500232.

The previous prime is 5245500187. The next prime is 5245500241. The reversal of 5245500233 is 3320055425.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5067731344 + 177768889 = 71188^2 + 13333^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5245500233 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 5245500196 and 5245500205.

It is not a weakly prime, because it can be changed into another prime (5245500833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2622750116 + 2622750117.

It is an arithmetic number, because the mean of its divisors is an integer number (2622750117).

Almost surely, 25245500233 is an apocalyptic number.

It is an amenable number.

5245500233 is a deficient number, since it is larger than the sum of its proper divisors (1).

5245500233 is an equidigital number, since it uses as much as digits as its factorization.

5245500233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 29.

The square root of 5245500233 is about 72425.8257322621. The cubic root of 5245500233 is about 1737.5166309883.

Adding to 5245500233 its reverse (3320055425), we get a palindrome (8565555658).

The spelling of 5245500233 in words is "five billion, two hundred forty-five million, five hundred thousand, two hundred thirty-three".