Base | Representation |
---|---|
bin | 10111110111111101000111… |
… | …10111001011011110100111 |
3 | 20212212222000122010120102012 |
4 | 23323332203313023132213 |
5 | 23340130233402111101 |
6 | 303354121230304435 |
7 | 14026003162315061 |
oct | 1373764367133647 |
9 | 225788018116365 |
10 | 52500134410151 |
11 | 1580120022073a |
12 | 5a7aa6495811b |
13 | 233a983c0603c |
14 | cd703d0a8731 |
15 | 6109b0470bbb |
hex | 2fbfa3dcb7a7 |
52500134410151 has 16 divisors (see below), whose sum is σ = 54845065604160. Its totient is φ = 50190972948480.
The previous prime is 52500134410111. The next prime is 52500134410159. The reversal of 52500134410151 is 15101443100525.
It is a de Polignac number, because none of the positive numbers 2k-52500134410151 is a prime.
It is a super-2 number, since 2×525001344101512 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52500134410159) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21359591 + ... + 23690343.
It is an arithmetic number, because the mean of its divisors is an integer number (3427816600260).
Almost surely, 252500134410151 is an apocalyptic number.
52500134410151 is a deficient number, since it is larger than the sum of its proper divisors (2344931194009).
52500134410151 is a wasteful number, since it uses less digits than its factorization.
52500134410151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2338426.
The product of its (nonzero) digits is 12000, while the sum is 32.
Adding to 52500134410151 its reverse (15101443100525), we get a palindrome (67601577510676).
The spelling of 52500134410151 in words is "fifty-two trillion, five hundred billion, one hundred thirty-four million, four hundred ten thousand, one hundred fifty-one".
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