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52503152001143 = 3137157291556217
BaseRepresentation
bin10111111000000010101111…
…01110011000000001110111
320212220020210221021002001112
423330001113232120001313
523340202423403014033
6303355340503545235
714026141023364334
oct1374012756300167
9225806727232045
1052503152001143
1115802509606498
125a7b56745b21b
13233b04513933c
14cd7247b6d98b
15610ada33bc48
hex2fc057b98077

52503152001143 has 16 divisors (see below), whose sum is σ = 56016113051904. Its totient is φ = 49121391271680.

The previous prime is 52503152001119. The next prime is 52503152001227. The reversal of 52503152001143 is 34110025130525.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52503152001143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52503152001343) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 145598030 + ... + 145958187.

It is an arithmetic number, because the mean of its divisors is an integer number (3501007065744).

Almost surely, 252503152001143 is an apocalyptic number.

52503152001143 is a deficient number, since it is larger than the sum of its proper divisors (3512961050761).

52503152001143 is a wasteful number, since it uses less digits than its factorization.

52503152001143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 291556442.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 52503152001143 its reverse (34110025130525), we get a palindrome (86613177131668).

The spelling of 52503152001143 in words is "fifty-two trillion, five hundred three billion, one hundred fifty-two million, one thousand, one hundred forty-three".

Divisors: 1 31 37 157 1147 4867 5809 180079 291556217 9038242727 10787580029 45774326069 334414980899 1419004108139 1693650064553 52503152001143