52503434115 has 128 divisors (see below), whose sum is σ = 100199890944. Its totient is φ = 23208768000.

The previous prime is 52503434059. The next prime is 52503434119. The reversal of 52503434115 is 51143430525.

52503434115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 52503434115 - 2⁷ = 52503433987 is a prime.

It is a super-2 number, since 2×52503434115² (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is not an unprimeable number, because it can be changed into a prime (52503434119) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 7878885 + ... + 7885545.

It is an arithmetic number, because the mean of its divisors is an integer number (782811648).

Almost surely, 2^52503434115 is an apocalyptic number.

52503434115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

52503434115 is a deficient number, since it is larger than the sum of its proper divisors (47696456829).

52503434115 is a wasteful number, since it uses less digits than its factorization.

52503434115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6801.

The product of its (nonzero) digits is 36000, while the sum is 33.

The spelling of 52503434115 in words is "fifty-two billion, five hundred three million, four hundred thirty-four thousand, one hundred fifteen".