Base | Representation |
---|---|
bin | 110000111001011100… |
… | …101101001110000111 |
3 | 12000112001110210122001 |
4 | 300321130231032013 |
5 | 1330011334342434 |
6 | 40041510450131 |
7 | 3536040553333 |
oct | 607134551607 |
9 | 160461423561 |
10 | 52503434119 |
11 | 202a2902174 |
12 | a213363947 |
13 | 4c496022a6 |
14 | 2780dd67c3 |
15 | 157454d114 |
hex | c3972d387 |
52503434119 has 2 divisors, whose sum is σ = 52503434120. Its totient is φ = 52503434118.
The previous prime is 52503434059. The next prime is 52503434129. The reversal of 52503434119 is 91143430525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52503434119 - 211 = 52503432071 is a prime.
It is a super-2 number, since 2×525034341192 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52503434129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26251717059 + 26251717060.
It is an arithmetic number, because the mean of its divisors is an integer number (26251717060).
Almost surely, 252503434119 is an apocalyptic number.
52503434119 is a deficient number, since it is larger than the sum of its proper divisors (1).
52503434119 is an equidigital number, since it uses as much as digits as its factorization.
52503434119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 37.
It can be divided in two parts, 525034 and 34119, that added together give a triangular number (559153 = T1057).
The spelling of 52503434119 in words is "fifty-two billion, five hundred three million, four hundred thirty-four thousand, one hundred nineteen".
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