Base | Representation |
---|---|
bin | 1100100001001… |
… | …0011000110101 |
3 | 10122210111002221 |
4 | 3020102120311 |
5 | 101420112432 |
6 | 5113202341 |
7 | 1205164141 |
oct | 310223065 |
9 | 118714087 |
10 | 52504117 |
11 | 27701136 |
12 | 157003b1 |
13 | ab54133 |
14 | 6d8a221 |
15 | 4921b97 |
hex | 3212635 |
52504117 has 4 divisors (see below), whose sum is σ = 52549036. Its totient is φ = 52459200.
The previous prime is 52504069. The next prime is 52504129. The reversal of 52504117 is 71140525.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 25816561 + 26687556 = 5081^2 + 5166^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52504117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52504091 and 52504100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52504157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20658 + ... + 23059.
It is an arithmetic number, because the mean of its divisors is an integer number (13137259).
Almost surely, 252504117 is an apocalyptic number.
It is an amenable number.
52504117 is a deficient number, since it is larger than the sum of its proper divisors (44919).
52504117 is a wasteful number, since it uses less digits than its factorization.
52504117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44918.
The product of its (nonzero) digits is 1400, while the sum is 25.
The square root of 52504117 is about 7245.9724675160. The cubic root of 52504117 is about 374.4534069424.
The spelling of 52504117 in words is "fifty-two million, five hundred four thousand, one hundred seventeen".
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