Base | Representation |
---|---|
bin | 100110001101001010001… |
… | …0101010111100000001011 |
3 | 200120222120221111002210202 |
4 | 1030122110111113200023 |
5 | 1142012410244234341 |
6 | 15100125315002415 |
7 | 1051240104135356 |
oct | 114322425274013 |
9 | 20528527432722 |
10 | 5250938664971 |
11 | 1744a01a9168a |
12 | 70980089940b |
13 | 2c12137667cc |
14 | 14220aadb29d |
15 | 918c7b5379b |
hex | 4c69455780b |
5250938664971 has 2 divisors, whose sum is σ = 5250938664972. Its totient is φ = 5250938664970.
The previous prime is 5250938664931. The next prime is 5250938664991. The reversal of 5250938664971 is 1794668390525.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5250938664971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5250938664898 and 5250938664907.
It is not a weakly prime, because it can be changed into another prime (5250938664901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625469332485 + 2625469332486.
It is an arithmetic number, because the mean of its divisors is an integer number (2625469332486).
It is a 1-persistent number, because it is pandigital, but 2⋅5250938664971 = 10501877329942 is not.
Almost surely, 25250938664971 is an apocalyptic number.
5250938664971 is a deficient number, since it is larger than the sum of its proper divisors (1).
5250938664971 is an equidigital number, since it uses as much as digits as its factorization.
5250938664971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97977600, while the sum is 65.
The spelling of 5250938664971 in words is "five trillion, two hundred fifty billion, nine hundred thirty-eight million, six hundred sixty-four thousand, nine hundred seventy-one".
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