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52511130000 = 2432547174903
BaseRepresentation
bin110000111001111010…
…000100000110010000
312000112120221210101200
4300321322010012100
51330020322130000
640042343431200
73536163145320
oct607172040620
9160476853350
1052511130000
11202a71891aa
12a215a55500
134c4b098174
14278203b280
15157506d500
hexc39e84190

52511130000 has 600 divisors, whose sum is σ = 222263952768. Its totient is φ = 11294208000.

The previous prime is 52511129987. The next prime is 52511130019. The reversal of 52511130000 is 3111525.

52511130000 is a `hidden beast` number, since 525 + 11 + 130 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (600).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 10707549 + ... + 10712451.

Almost surely, 252511130000 is an apocalyptic number.

52511130000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 52511130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (111131976384).

52511130000 is an abundant number, since it is smaller than the sum of its proper divisors (169752822768).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

52511130000 is a wasteful number, since it uses less digits than its factorization.

52511130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4961 (or 4937 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

Adding to 52511130000 its reverse (3111525), we get a palindrome (52514241525).

The spelling of 52511130000 in words is "fifty-two billion, five hundred eleven million, one hundred thirty thousand".