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5251251045103 = 741130713999267
BaseRepresentation
bin100110001101010011011…
…1101000000001011101111
3200121000101201021122210021
41030122212331000023233
51142014030231420403
615100220314223011
71051250616256540
oct114324675001357
920530351248707
105251251045103
111745052351488
12709889424a67
132c12633aa61b
1414223a3b44c7
15918e52aa8bd
hex4c6a6f402ef

5251251045103 has 16 divisors (see below), whose sum is σ = 6152510294784. Its totient is φ = 4387929935040.

The previous prime is 5251251045091. The next prime is 5251251045109. The reversal of 5251251045103 is 3015401521525.

It is a cyclic number.

It is not a de Polignac number, because 5251251045103 - 25 = 5251251045071 is a prime.

It is a super-3 number, since 3×52512510451033 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5251251045109) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6624525 + ... + 7374742.

It is an arithmetic number, because the mean of its divisors is an integer number (384531893424).

Almost surely, 25251251045103 is an apocalyptic number.

5251251045103 is a deficient number, since it is larger than the sum of its proper divisors (901259249681).

5251251045103 is a wasteful number, since it uses less digits than its factorization.

5251251045103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14000622.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 5251251045103 its reverse (3015401521525), we get a palindrome (8266652566628).

The spelling of 5251251045103 in words is "five trillion, two hundred fifty-one billion, two hundred fifty-one million, forty-five thousand, one hundred three".

Divisors: 1 7 41 287 1307 9149 53587 375109 13999267 97994869 573969947 4017789629 18297041969 128079293783 750178720729 5251251045103