Base | Representation |
---|---|
bin | 100110001101010011011… |
… | …1101000000001011101111 |
3 | 200121000101201021122210021 |
4 | 1030122212331000023233 |
5 | 1142014030231420403 |
6 | 15100220314223011 |
7 | 1051250616256540 |
oct | 114324675001357 |
9 | 20530351248707 |
10 | 5251251045103 |
11 | 1745052351488 |
12 | 709889424a67 |
13 | 2c12633aa61b |
14 | 14223a3b44c7 |
15 | 918e52aa8bd |
hex | 4c6a6f402ef |
5251251045103 has 16 divisors (see below), whose sum is σ = 6152510294784. Its totient is φ = 4387929935040.
The previous prime is 5251251045091. The next prime is 5251251045109. The reversal of 5251251045103 is 3015401521525.
It is a cyclic number.
It is not a de Polignac number, because 5251251045103 - 25 = 5251251045071 is a prime.
It is a super-3 number, since 3×52512510451033 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5251251045109) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6624525 + ... + 7374742.
It is an arithmetic number, because the mean of its divisors is an integer number (384531893424).
Almost surely, 25251251045103 is an apocalyptic number.
5251251045103 is a deficient number, since it is larger than the sum of its proper divisors (901259249681).
5251251045103 is a wasteful number, since it uses less digits than its factorization.
5251251045103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14000622.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 5251251045103 its reverse (3015401521525), we get a palindrome (8266652566628).
The spelling of 5251251045103 in words is "five trillion, two hundred fifty-one billion, two hundred fifty-one million, forty-five thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •