Base | Representation |
---|---|
bin | 110000111010000001… |
… | …100101010101001111 |
3 | 12000112201122221021200 |
4 | 300322001211111033 |
5 | 1330021323214020 |
6 | 40042454000543 |
7 | 3536215665135 |
oct | 607201452517 |
9 | 160481587250 |
10 | 52513101135 |
11 | 202a8305140 |
12 | a216646153 |
13 | 4c4b608411 |
14 | 27823d1755 |
15 | 157530c590 |
hex | c3a06554f |
52513101135 has 24 divisors (see below), whose sum is σ = 99297501264. Its totient is φ = 25460897280.
The previous prime is 52513101127. The next prime is 52513101191. The reversal of 52513101135 is 53110131525.
52513101135 is a `hidden beast` number, since 5 + 2 + 513 + 10 + 1 + 135 = 666.
It is not a de Polignac number, because 52513101135 - 23 = 52513101127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52513101099 and 52513101108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 53043042 + ... + 53044031.
It is an arithmetic number, because the mean of its divisors is an integer number (4137395886).
Almost surely, 252513101135 is an apocalyptic number.
52513101135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
52513101135 is a deficient number, since it is larger than the sum of its proper divisors (46784400129).
52513101135 is a wasteful number, since it uses less digits than its factorization.
52513101135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106087095 (or 106087092 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
The spelling of 52513101135 in words is "fifty-two billion, five hundred thirteen million, one hundred one thousand, one hundred thirty-five".
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