Base | Representation |
---|---|
bin | 111011101101011011011101… |
… | …0011001110111011010110100 |
3 | 2112212121220002011110200002201 |
4 | 1313122312322121313122310 |
5 | 1022320043120000243012 |
6 | 5101011340431314244 |
7 | 215425254534463252 |
oct | 16732667231673264 |
9 | 2485556064420081 |
10 | 525213203134132 |
11 | 142392739986667 |
12 | 4aaa5a0707b984 |
13 | 1970a514543546 |
14 | 939a6518675d2 |
15 | 40ac002604857 |
hex | 1ddadba6776b4 |
525213203134132 has 48 divisors (see below), whose sum is σ = 928423022284800. Its totient is φ = 259964304400640.
The previous prime is 525213203134063. The next prime is 525213203134177. The reversal of 525213203134132 is 231431302312525.
It is a junction number, because it is equal to n+sod(n) for n = 525213203134091 and 525213203134100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 271652544 + ... + 273579112.
It is an arithmetic number, because the mean of its divisors is an integer number (19342146297600).
Almost surely, 2525213203134132 is an apocalyptic number.
It is an amenable number.
525213203134132 is a deficient number, since it is larger than the sum of its proper divisors (403209819150668).
525213203134132 is a wasteful number, since it uses less digits than its factorization.
525213203134132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1928496 (or 1928494 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 37.
Adding to 525213203134132 its reverse (231431302312525), we get a palindrome (756644505446657).
The spelling of 525213203134132 in words is "five hundred twenty-five trillion, two hundred thirteen billion, two hundred three million, one hundred thirty-four thousand, one hundred thirty-two".
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