Base | Representation |
---|---|
bin | 100110001110100101100… |
… | …0111101100101011010111 |
3 | 200121021111122220220222022 |
4 | 1030131023013230223113 |
5 | 1142040200324442330 |
6 | 15101353503523355 |
7 | 1051406102202032 |
oct | 114351307545327 |
9 | 20537448826868 |
10 | 5254005312215 |
11 | 17462360330a0 |
12 | 70a3178b955b |
13 | 2c15b1bb478a |
14 | 14241c0d2019 |
15 | 91a06eaeae5 |
hex | 4c74b1ecad7 |
5254005312215 has 16 divisors (see below), whose sum is σ = 6878149672320. Its totient is φ = 3820995282720.
The previous prime is 5254005312181. The next prime is 5254005312229. The reversal of 5254005312215 is 5122135004525.
It is a happy number.
It is not a de Polignac number, because 5254005312215 - 26 = 5254005312151 is a prime.
It is a super-4 number, since 4×52540053122154 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 921932 + ... + 3370158.
It is an arithmetic number, because the mean of its divisors is an integer number (429884354520).
Almost surely, 25254005312215 is an apocalyptic number.
5254005312215 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5254005312215 is a deficient number, since it is larger than the sum of its proper divisors (1624144360105).
5254005312215 is a wasteful number, since it uses less digits than its factorization.
5254005312215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2487262.
The product of its (nonzero) digits is 60000, while the sum is 35.
The spelling of 5254005312215 in words is "five trillion, two hundred fifty-four billion, five million, three hundred twelve thousand, two hundred fifteen".
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