Base | Representation |
---|---|
bin | 110000111011101001… |
… | …100010100000010011 |
3 | 12000121121221110011122 |
4 | 300323221202200103 |
5 | 1330100312240111 |
6 | 40045310032455 |
7 | 3536666425232 |
oct | 607351424023 |
9 | 160547843148 |
10 | 52540352531 |
11 | 20311728557 |
12 | a2237a872b |
13 | 4c5415a2c4 |
14 | 2785c86b19 |
15 | 15778e1cdb |
hex | c3ba62813 |
52540352531 has 2 divisors, whose sum is σ = 52540352532. Its totient is φ = 52540352530.
The previous prime is 52540352503. The next prime is 52540352549. The reversal of 52540352531 is 13525304525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 52540352531 - 218 = 52540090387 is a prime.
It is a super-2 number, since 2×525403525312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52540352491 and 52540352500.
It is not a weakly prime, because it can be changed into another prime (52540352581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26270176265 + 26270176266.
It is an arithmetic number, because the mean of its divisors is an integer number (26270176266).
Almost surely, 252540352531 is an apocalyptic number.
52540352531 is a deficient number, since it is larger than the sum of its proper divisors (1).
52540352531 is an equidigital number, since it uses as much as digits as its factorization.
52540352531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 52540352531 in words is "fifty-two billion, five hundred forty million, three hundred fifty-two thousand, five hundred thirty-one".
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