Base | Representation |
---|---|
bin | 10111111001001001111001… |
… | …01001110000111001101011 |
3 | 20220000220102012021011001212 |
4 | 23330210330221300321223 |
5 | 23341314142220410011 |
6 | 303425055241303335 |
7 | 14031662460362366 |
oct | 1374447451607153 |
9 | 226026365234055 |
10 | 52541352513131 |
11 | 1581773181a559 |
12 | 5a86a48794b4b |
13 | 234182244a8a1 |
14 | cd902d3590dd |
15 | 611ac3d6c08b |
hex | 2fc93ca70e6b |
52541352513131 has 2 divisors, whose sum is σ = 52541352513132. Its totient is φ = 52541352513130.
The previous prime is 52541352513103. The next prime is 52541352513203. The reversal of 52541352513131 is 13131525314525.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52541352513131 is a prime.
It is a super-2 number, since 2×525413525131312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (52541352513931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26270676256565 + 26270676256566.
It is an arithmetic number, because the mean of its divisors is an integer number (26270676256566).
Almost surely, 252541352513131 is an apocalyptic number.
52541352513131 is a deficient number, since it is larger than the sum of its proper divisors (1).
52541352513131 is an equidigital number, since it uses as much as digits as its factorization.
52541352513131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 270000, while the sum is 41.
Adding to 52541352513131 its reverse (13131525314525), we get a palindrome (65672877827656).
The spelling of 52541352513131 in words is "fifty-two trillion, five hundred forty-one billion, three hundred fifty-two million, five hundred thirteen thousand, one hundred thirty-one".
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