Base | Representation |
---|---|
bin | 1111010011000000110… |
… | …10001100100100100001 |
3 | 1212020200012200202210221 |
4 | 13221200122030210201 |
5 | 32102413443140311 |
6 | 1041243042523041 |
7 | 52654641644125 |
oct | 7514032144441 |
9 | 1766605622727 |
10 | 525603490081 |
11 | 1929a851655a |
12 | 85a47666481 |
13 | 3a7447025c7 |
14 | 1b6217c1585 |
15 | da137b2671 |
hex | 7a6068c921 |
525603490081 has 2 divisors, whose sum is σ = 525603490082. Its totient is φ = 525603490080.
The previous prime is 525603490073. The next prime is 525603490133. The reversal of 525603490081 is 180094306525.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 400771294225 + 124832195856 = 633065^2 + 353316^2 .
It is a cyclic number.
It is not a de Polignac number, because 525603490081 - 23 = 525603490073 is a prime.
It is a super-2 number, since 2×5256034900812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (525603490031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262801745040 + 262801745041.
It is an arithmetic number, because the mean of its divisors is an integer number (262801745041).
Almost surely, 2525603490081 is an apocalyptic number.
It is an amenable number.
525603490081 is a deficient number, since it is larger than the sum of its proper divisors (1).
525603490081 is an equidigital number, since it uses as much as digits as its factorization.
525603490081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 43.
The spelling of 525603490081 in words is "five hundred twenty-five billion, six hundred three million, four hundred ninety thousand, eighty-one".
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