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525680537 is a prime number
BaseRepresentation
bin11111010101010…
…011111110011001
31100122011100010112
4133111103332121
52034033234122
6124055054105
716012132214
oct3725237631
91318140115
10525680537
1124a807628
12128071335
1384ba6c95
144db5c77b
153123c2e2
hex1f553f99

525680537 has 2 divisors, whose sum is σ = 525680538. Its totient is φ = 525680536.

The previous prime is 525680509. The next prime is 525680563. The reversal of 525680537 is 735086525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 275692816 + 249987721 = 16604^2 + 15811^2 .

It is a cyclic number.

It is not a de Polignac number, because 525680537 - 222 = 521486233 is a prime.

It is a super-3 number, since 3×5256805373 (a number of 27 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 525680494 and 525680503.

It is not a weakly prime, because it can be changed into another prime (525680567) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262840268 + 262840269.

It is an arithmetic number, because the mean of its divisors is an integer number (262840269).

Almost surely, 2525680537 is an apocalyptic number.

It is an amenable number.

525680537 is a deficient number, since it is larger than the sum of its proper divisors (1).

525680537 is an equidigital number, since it uses as much as digits as its factorization.

525680537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252000, while the sum is 41.

The square root of 525680537 is about 22927.7242001905. The cubic root of 525680537 is about 807.0627432666.

The spelling of 525680537 in words is "five hundred twenty-five million, six hundred eighty thousand, five hundred thirty-seven".