Base | Representation |
---|---|
bin | 10111111001111111010101… |
… | …10001000100100100010111 |
3 | 20220010122110201100200012000 |
4 | 23330333222301010210113 |
5 | 23342301422111434210 |
6 | 303450202232130343 |
7 | 14034026453436321 |
oct | 1374775261044427 |
9 | 226118421320160 |
10 | 52570043468055 |
11 | 15828915048653 |
12 | 5a905152369b3 |
13 | 234444555b9a9 |
14 | cda5919aa611 |
15 | 612702abaac0 |
hex | 2fcfeac44917 |
52570043468055 has 32 divisors (see below), whose sum is σ = 93559550438400. Its totient is φ = 28006847901216.
The previous prime is 52570043468053. The next prime is 52570043468093. The reversal of 52570043468055 is 55086434007525.
52570043468055 is a `hidden beast` number, since 5 + 2 + 570 + 0 + 4 + 3 + 4 + 68 + 0 + 5 + 5 = 666.
It is not a de Polignac number, because 52570043468055 - 21 = 52570043468053 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52570043467992 and 52570043468010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52570043468053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 211740859 + ... + 211988988.
It is an arithmetic number, because the mean of its divisors is an integer number (2923735951200).
Almost surely, 252570043468055 is an apocalyptic number.
52570043468055 is a deficient number, since it is larger than the sum of its proper divisors (40989506970345).
52570043468055 is a wasteful number, since it uses less digits than its factorization.
52570043468055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 423730780 (or 423730774 counting only the distinct ones).
The product of its (nonzero) digits is 20160000, while the sum is 54.
The spelling of 52570043468055 in words is "fifty-two trillion, five hundred seventy billion, forty-three million, four hundred sixty-eight thousand, fifty-five".
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