Base | Representation |
---|---|
bin | 110001000001100111… |
… | …010001010111010011 |
3 | 12000212121020110202111 |
4 | 301001213101113103 |
5 | 1330301421440311 |
6 | 40103242530151 |
7 | 3542323125061 |
oct | 610147212723 |
9 | 160777213674 |
10 | 52640421331 |
11 | 20363166743 |
12 | a251206957 |
13 | 4c6bac6204 |
14 | 2795295031 |
15 | 15815abd21 |
hex | c419d15d3 |
52640421331 has 2 divisors, whose sum is σ = 52640421332. Its totient is φ = 52640421330.
The previous prime is 52640421319. The next prime is 52640421349. The reversal of 52640421331 is 13312404625.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52640421331 - 25 = 52640421299 is a prime.
It is a super-2 number, since 2×526404213312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52640421293 and 52640421302.
It is not a weakly prime, because it can be changed into another prime (52640521331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26320210665 + 26320210666.
It is an arithmetic number, because the mean of its divisors is an integer number (26320210666).
Almost surely, 252640421331 is an apocalyptic number.
52640421331 is a deficient number, since it is larger than the sum of its proper divisors (1).
52640421331 is an equidigital number, since it uses as much as digits as its factorization.
52640421331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 52640421331 its reverse (13312404625), we get a palindrome (65952825956).
The spelling of 52640421331 in words is "fifty-two billion, six hundred forty million, four hundred twenty-one thousand, three hundred thirty-one".
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