Base | Representation |
---|---|
bin | 100110010101011011001… |
… | …0111010101101011110111 |
3 | 200122200102000202202021222 |
4 | 1030222312113111223313 |
5 | 1142310234001220333 |
6 | 15112222540300555 |
7 | 1052436015425126 |
oct | 114526627255367 |
9 | 20580360682258 |
10 | 5268689476343 |
11 | 1751490944a27 |
12 | 71113554175b |
13 | 2c2ab2179aa7 |
14 | 1430123bdabd |
15 | 920b61d8298 |
hex | 4cab65d5af7 |
5268689476343 has 16 divisors (see below), whose sum is σ = 5384500531200. Its totient is φ = 5154078084960.
The previous prime is 5268689476327. The next prime is 5268689476357. The reversal of 5268689476343 is 3436749868625.
It is a cyclic number.
It is not a de Polignac number, because 5268689476343 - 24 = 5268689476327 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (71).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5268689476313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16709930 + ... + 17022312.
It is an arithmetic number, because the mean of its divisors is an integer number (336531283200).
Almost surely, 25268689476343 is an apocalyptic number.
5268689476343 is a deficient number, since it is larger than the sum of its proper divisors (115811054857).
5268689476343 is a wasteful number, since it uses less digits than its factorization.
5268689476343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 314302.
The product of its digits is 1254113280, while the sum is 71.
The spelling of 5268689476343 in words is "five trillion, two hundred sixty-eight billion, six hundred eighty-nine million, four hundred seventy-six thousand, three hundred forty-three".
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