Base | Representation |
---|---|
bin | 100110010101011011001… |
… | …0111010101101011100111 |
3 | 200122200102000202202021101 |
4 | 1030222312113111223213 |
5 | 1142310234001220302 |
6 | 15112222540300531 |
7 | 1052436015425104 |
oct | 114526627255347 |
9 | 20580360682241 |
10 | 5268689476327 |
11 | 1751490944a12 |
12 | 711135541747 |
13 | 2c2ab2179a94 |
14 | 1430123bdaab |
15 | 920b61d8287 |
hex | 4cab65d5ae7 |
5268689476327 has 2 divisors, whose sum is σ = 5268689476328. Its totient is φ = 5268689476326.
The previous prime is 5268689476319. The next prime is 5268689476357. The reversal of 5268689476327 is 7236749868625.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5268689476327 - 23 = 5268689476319 is a prime.
It is a super-3 number, since 3×52686894763273 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5268689476327.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5268689476357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2634344738163 + 2634344738164.
It is an arithmetic number, because the mean of its divisors is an integer number (2634344738164).
Almost surely, 25268689476327 is an apocalyptic number.
5268689476327 is a deficient number, since it is larger than the sum of its proper divisors (1).
5268689476327 is an equidigital number, since it uses as much as digits as its factorization.
5268689476327 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1463132160, while the sum is 73.
The spelling of 5268689476327 in words is "five trillion, two hundred sixty-eight billion, six hundred eighty-nine million, four hundred seventy-six thousand, three hundred twenty-seven".
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