Base | Representation |
---|---|
bin | 1001110100001011… |
… | …11111100111101011 |
3 | 111121020201021201212 |
4 | 10322011333213223 |
5 | 41243010222011 |
6 | 2230522103335 |
7 | 244405002152 |
oct | 47205774753 |
9 | 14536637655 |
10 | 5269617131 |
11 | 226461a389 |
12 | 103094ab4b |
13 | 65c97c35c |
14 | 37dc06599 |
15 | 20c96308b |
hex | 13a17f9eb |
5269617131 has 2 divisors, whose sum is σ = 5269617132. Its totient is φ = 5269617130.
The previous prime is 5269617113. The next prime is 5269617139. The reversal of 5269617131 is 1317169625.
Together with previous prime (5269617113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5269617131 is a prime.
It is a super-2 number, since 2×52696171312 = 55537729414657342322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5269617139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2634808565 + 2634808566.
It is an arithmetic number, because the mean of its divisors is an integer number (2634808566).
Almost surely, 25269617131 is an apocalyptic number.
5269617131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5269617131 is an equidigital number, since it uses as much as digits as its factorization.
5269617131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 68040, while the sum is 41.
The square root of 5269617131 is about 72592.1285746602. The cubic root of 5269617131 is about 1740.1753831892.
The spelling of 5269617131 in words is "five billion, two hundred sixty-nine million, six hundred seventeen thousand, one hundred thirty-one".
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