Base | Representation |
---|---|
bin | 110001000111101000… |
… | …101000011011100101 |
3 | 12001010122022211001002 |
4 | 301013220220123211 |
5 | 1331003302110003 |
6 | 40121252043045 |
7 | 3544660565564 |
oct | 610750503345 |
9 | 161118284032 |
10 | 52741441253 |
11 | 20405194486 |
12 | a27b003485 |
13 | 4c86a06007 |
14 | 27a486dbdb |
15 | 158a3b3a88 |
hex | c47a286e5 |
52741441253 has 4 divisors (see below), whose sum is σ = 53156728320. Its totient is φ = 52326154188.
The previous prime is 52741441219. The next prime is 52741441307. The reversal of 52741441253 is 35214414725.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 52741441253 - 210 = 52741440229 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52741441453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207643343 + ... + 207643596.
It is an arithmetic number, because the mean of its divisors is an integer number (13289182080).
Almost surely, 252741441253 is an apocalyptic number.
It is an amenable number.
52741441253 is a deficient number, since it is larger than the sum of its proper divisors (415287067).
52741441253 is a wasteful number, since it uses less digits than its factorization.
52741441253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 415287066.
The product of its digits is 134400, while the sum is 38.
Adding to 52741441253 its reverse (35214414725), we get a palindrome (87955855978).
The spelling of 52741441253 in words is "fifty-two billion, seven hundred forty-one million, four hundred forty-one thousand, two hundred fifty-three".
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