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52741441253 = 127415286939
BaseRepresentation
bin110001000111101000…
…101000011011100101
312001010122022211001002
4301013220220123211
51331003302110003
640121252043045
73544660565564
oct610750503345
9161118284032
1052741441253
1120405194486
12a27b003485
134c86a06007
1427a486dbdb
15158a3b3a88
hexc47a286e5

52741441253 has 4 divisors (see below), whose sum is σ = 53156728320. Its totient is φ = 52326154188.

The previous prime is 52741441219. The next prime is 52741441307. The reversal of 52741441253 is 35214414725.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52741441253 - 210 = 52741440229 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52741441453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 207643343 + ... + 207643596.

It is an arithmetic number, because the mean of its divisors is an integer number (13289182080).

Almost surely, 252741441253 is an apocalyptic number.

It is an amenable number.

52741441253 is a deficient number, since it is larger than the sum of its proper divisors (415287067).

52741441253 is a wasteful number, since it uses less digits than its factorization.

52741441253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 415287066.

The product of its digits is 134400, while the sum is 38.

Adding to 52741441253 its reverse (35214414725), we get a palindrome (87955855978).

The spelling of 52741441253 in words is "fifty-two billion, seven hundred forty-one million, four hundred forty-one thousand, two hundred fifty-three".

Divisors: 1 127 415286939 52741441253