Base | Representation |
---|---|
bin | 100110011100100011110… |
… | …1111101100111110101001 |
3 | 200201010221222112211221201 |
4 | 1030321013233230332221 |
5 | 1143033124421231132 |
6 | 15123235310404201 |
7 | 1053520531231345 |
oct | 114710757547651 |
9 | 20633858484851 |
10 | 5284013461417 |
11 | 1757a349327a9 |
12 | 7140b1500661 |
13 | 2c4384b70b92 |
14 | 143a6765c625 |
15 | 926b16982e7 |
hex | 4ce47becfa9 |
5284013461417 has 2 divisors, whose sum is σ = 5284013461418. Its totient is φ = 5284013461416.
The previous prime is 5284013461393. The next prime is 5284013461501. The reversal of 5284013461417 is 7141643104825.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2705561129881 + 2578452331536 = 1644859^2 + 1605756^2 .
It is a cyclic number.
It is not a de Polignac number, because 5284013461417 - 211 = 5284013459369 is a prime.
It is not a weakly prime, because it can be changed into another prime (5284013461817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2642006730708 + 2642006730709.
It is an arithmetic number, because the mean of its divisors is an integer number (2642006730709).
Almost surely, 25284013461417 is an apocalyptic number.
It is an amenable number.
5284013461417 is a deficient number, since it is larger than the sum of its proper divisors (1).
5284013461417 is an equidigital number, since it uses as much as digits as its factorization.
5284013461417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 46.
The spelling of 5284013461417 in words is "five trillion, two hundred eighty-four billion, thirteen million, four hundred sixty-one thousand, four hundred seventeen".
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