Base | Representation |
---|---|
bin | 1100100110110… |
… | …1101100100001 |
3 | 10200111111010122 |
4 | 3021231230201 |
5 | 102014044423 |
6 | 5125210025 |
7 | 1211312411 |
oct | 311555441 |
9 | 120444118 |
10 | 52878113 |
11 | 27937122 |
12 | 15860915 |
13 | ac55432 |
14 | 7046641 |
15 | 49978c8 |
hex | 326db21 |
52878113 has 2 divisors, whose sum is σ = 52878114. Its totient is φ = 52878112.
The previous prime is 52878079. The next prime is 52878131. The reversal of 52878113 is 31187825.
52878113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (52878131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52823824 + 54289 = 7268^2 + 233^2 .
It is a cyclic number.
It is not a de Polignac number, because 52878113 - 28 = 52877857 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (52874113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26439056 + 26439057.
It is an arithmetic number, because the mean of its divisors is an integer number (26439057).
Almost surely, 252878113 is an apocalyptic number.
It is an amenable number.
52878113 is a deficient number, since it is larger than the sum of its proper divisors (1).
52878113 is an equidigital number, since it uses as much as digits as its factorization.
52878113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13440, while the sum is 35.
The square root of 52878113 is about 7271.7338372633. The cubic root of 52878113 is about 375.3404032046.
The spelling of 52878113 in words is "fifty-two million, eight hundred seventy-eight thousand, one hundred thirteen".
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