Base | Representation |
---|---|
bin | 100110011111100101001… |
… | …1001110011110110010011 |
3 | 200201202201002001210210101 |
4 | 1030333022121303312103 |
5 | 1143134421112124404 |
6 | 15130231122313231 |
7 | 1054140351211654 |
oct | 114771231636623 |
9 | 20652632053711 |
10 | 5290500504979 |
11 | 175a763680628 |
12 | 715401ab8817 |
13 | 2c4b79b065b1 |
14 | 1440c100d52b |
15 | 92940e3a2a4 |
hex | 4cfca673d93 |
5290500504979 has 2 divisors, whose sum is σ = 5290500504980. Its totient is φ = 5290500504978.
The previous prime is 5290500504931. The next prime is 5290500505033. The reversal of 5290500504979 is 9794050050925.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5290500504979 - 29 = 5290500504467 is a prime.
It is a super-3 number, since 3×52905005049793 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5290500504929) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2645250252489 + 2645250252490.
It is an arithmetic number, because the mean of its divisors is an integer number (2645250252490).
Almost surely, 25290500504979 is an apocalyptic number.
5290500504979 is a deficient number, since it is larger than the sum of its proper divisors (1).
5290500504979 is an equidigital number, since it uses as much as digits as its factorization.
5290500504979 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5103000, while the sum is 55.
The spelling of 5290500504979 in words is "five trillion, two hundred ninety billion, five hundred million, five hundred four thousand, nine hundred seventy-nine".
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