Base | Representation |
---|---|
bin | 110001010110101100… |
… | …011101001000100001 |
3 | 12001210020202022010212 |
4 | 301112230131020201 |
5 | 1332012442224133 |
6 | 40202315303505 |
7 | 3554146301333 |
oct | 612654351041 |
9 | 161706668125 |
10 | 52994101793 |
11 | 20524875046 |
12 | a32b74ab95 |
13 | 4cc716a6a9 |
14 | 27ca23d453 |
15 | 15a2671148 |
hex | c56b1d221 |
52994101793 has 2 divisors, whose sum is σ = 52994101794. Its totient is φ = 52994101792.
The previous prime is 52994101759. The next prime is 52994101847. The reversal of 52994101793 is 39710149925.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52621148449 + 372953344 = 229393^2 + 19312^2 .
It is a cyclic number.
It is not a de Polignac number, because 52994101793 - 212 = 52994097697 is a prime.
It is not a weakly prime, because it can be changed into another prime (52994101723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26497050896 + 26497050897.
It is an arithmetic number, because the mean of its divisors is an integer number (26497050897).
Almost surely, 252994101793 is an apocalyptic number.
It is an amenable number.
52994101793 is a deficient number, since it is larger than the sum of its proper divisors (1).
52994101793 is an equidigital number, since it uses as much as digits as its factorization.
52994101793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 612360, while the sum is 50.
The spelling of 52994101793 in words is "fifty-two billion, nine hundred ninety-four million, one hundred one thousand, seven hundred ninety-three".
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