53000305113141 has 6 divisors (see below), whose sum is σ = 76555996274550. Its totient is φ = 35333536742088.

The previous prime is 53000305113083. The next prime is 53000305113167. The reversal of 53000305113141 is 14131150300035.

It is a happy number.

53000305113141 is a `hidden beast` number, since 5 + 3 + 0 + 0 + 0 + 3 + 0 + 511 + 3 + 141 = 666.

It can be written as a sum of positive squares in only one way, i.e., 30942685638225 + 22057619474916 = 5562615^2 + 4696554^2 .

It is not a de Polignac number, because 53000305113141 - 2⁷ = 53000305113013 is a prime.

It is a super-3 number, since 3×53000305113141³ (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53000305113641) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2944461395166 + ... + 2944461395183.

It is an arithmetic number, because the mean of its divisors is an integer number (12759332712425).

Almost surely, 2^{53000305113141} is an apocalyptic number.

It is an amenable number.

53000305113141 is a deficient number, since it is larger than the sum of its proper divisors (23555691161409).

53000305113141 is a wasteful number, since it uses less digits than its factorization.

53000305113141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5888922790355 (or 5888922790352 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

Adding to 53000305113141 its reverse (14131150300035), we get a palindrome (67131455413176).

The spelling of 53000305113141 in words is "fifty-three trillion, three hundred five million, one hundred thirteen thousand, one hundred forty-one".