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53000504003 is a prime number
BaseRepresentation
bin110001010111000100…
…111000001011000011
312001210200210120022202
4301113010320023003
51332021112112003
640203104423415
73554254564556
oct612704701303
9161720716282
1053000504003
1120528448127
12a331917b6b
134cc859c795
1427cb02869d
1515a2ed8088
hexc571382c3

53000504003 has 2 divisors, whose sum is σ = 53000504004. Its totient is φ = 53000504002.

The previous prime is 53000503999. The next prime is 53000504057. The reversal of 53000504003 is 30040500035.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53000504003 - 22 = 53000503999 is a prime.

It is not a weakly prime, because it can be changed into another prime (53000506003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26500252001 + 26500252002.

It is an arithmetic number, because the mean of its divisors is an integer number (26500252002).

Almost surely, 253000504003 is an apocalyptic number.

53000504003 is a deficient number, since it is larger than the sum of its proper divisors (1).

53000504003 is an equidigital number, since it uses as much as digits as its factorization.

53000504003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 20.

The spelling of 53000504003 in words is "fifty-three billion, five hundred four thousand, three".